-10m^2-17m+6=0

Solution for -10m^2-17m+6=0 equation:

-10m^2-17m+6=0

a = -10; b = -17; c = +6;
Δ = b2-4ac
Δ = -172-4·(-10)·6
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-23}{2*-10}=\frac{-6}{-20}
=3/10
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+23}{2*-10}=\frac{40}{-20}
=-2
$